【基础级练习题9】 原创:Joseflin先生(台湾) 3 x& z2 u, F: u; p y; e$ S9 E
% E% A D0 s9 R8 M- a% Y. \( i6 l
求:
. u# r7 H6 j! H2 {' u1. 斜线区域A之面积为何?
$ {# Z2 _ \% \4 C+ D (A)49.1248 (B)45.1248 (C)43.1248 (D)47.1248
( g m B$ i, H+ H' E( Y3 r0 s2 斜线区域B之面积为何? mm2 $ h1 Y& t2 `$ [9 G( x v+ J( O
3. 圆C之半径值为何? mm ! m7 R. K6 u( ^0 J& C. ~0 z
4. ED圆弧之弧长为何? mm
0 A% O* t0 b4 B7 m3 o5. F点之坐标为何?
) ]" K! Q7 ?% I' F5 ~! F [ (A)1.11,20.23 (B)1.33,17.45 (C)0.72,23.32 (D)0.87,18.55 6 V8 R$ P7 Z2 E" C7 \; ^5 M7 f: ?
【基础级练习题9】答案: 3 T7 t2 a/ K2 w
1. 斜线区域A之面积 = 47.1248,就是(D)
2 Y9 K1 a9 b5 ~0 y& e) n2. 斜线区域B之面积 = 68.4104 * {7 s; ?; X/ f0 P. z2 P7 R
3. 圆C之半径值 = 0.2592 + ~; {2 [0 i$ {/ }
4. ED圆弧之弧长 = 14.1214
' @9 I- N" T1 D, r8 e% T$ _7 M' X! y5. F点之坐标 = 0.72,23.32,就是(C)
8 k1 [% g- Y9 O, V8 t" Z% W2 s* R" n: p* X/ y z8 g
【基础级练习题9】解题要点、制图步骤:
6 c q8 m- R+ u+ [- r4 b: h8 \& S; z. o( j
% _0 r' Z" x4 M% ]& u
|